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#29
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![]() Quote:
478 kph TAS x 0.539956803 nautical miles at +5C = 258KTAS We don't have a piece of the puzzle which is the atmospheric pressure for that day. I am not looking for it but if somebody finds it, I will refine the calculation. 258KTAS x 1.0299 SMOE for our density altitude Temperature difference = 265 KTAS 265KTAS / 0.539956803 = 492kph 492 kph is within 1% of Mtt stated mean of 500kph over a range of 5%. If we had the pressure and I wasn't using some quick rules of thumb of a standard atmosphere chart but did the full calcs, I bet it would give even better agreement. The French might have had an optimistic performing Bf-109!! The French test results give very good agreement with Mtt's published figures for the type. |
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