Why still no dive acceleration difference?

[FC99]

Originally Posted by BlackBerry

Fw190A8

m----mass,4272 kg,max load for a standard A8,100% fuel
A----dive angle
p----engine output,1953 HP@sea level
r----propeller efficeincy=0.8=80%
Vmax ----max level speed at SL, 578km/h=160.6m/s
d----drag coefficient
g----gravity, 9.8 m/s^2
t---- engine thrust, N


when level flys at Vmax, fw190a8 in equilirium, zero acceleratiom, all forces are balanced.

t=P*r/V=1953*735*0.8/160.5=7155N

m*g* sin(0)+t=d*Vmax^2

d=t/Vmax^2=7155/160.5^2=0.2778

Drag coefficient is wrong.
In level flight drag = thrust.
D=0.5*density*speed^2*drag_coefficient*reference_a rea
From the above equation calculate drag coefficient and use it to calculate drag at different speeds and altitudes. What you called as "drag coefficient" ans used throughout the different examples is not correct.