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#1
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Yes, that works. But even you can get same propeller efficiency as 190, your weight is too great to overcome, Propellerthrust/weight is still inferior to 190's. We need to know if 190's airscrew tip compressibility loss is modelled or not at high mach number where 190's huge "advance ratio" making efficiency even worse than P47's. Last edited by BlackBerry; 05-12-2012 at 06:11 PM. |
#2
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agree, but better to do it than not if your p47 guy. for 190 guy, you have revealed something that I think goes ignored. sometimes it is good to over ride the vdm auto prop pitch control and go to manual mode for same reason, to keep tip speeds at optimal ranges.
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#3
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Thanks to BlackBerry and everyone,
all your threads have done greatly to help me to understand more. and may be there is a chance to involve the Prop calculation in IL2 to knock down Cliff of Dover and be the most perfect all the way? Sorry for offensive language to someone l I am tricky and want this topic to enjoy a long life and drag more men to research in their full strenth, So that I deliberately use somewhat offensive language. sorry again JTD or so |
#4
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Again, NACA Figure24, Both fw190's 3 meter prop. and p47's 4-meter prop @19500ft , 1350rpm for propeller CSP, 1)A point=126m/s TAS=453km/h TAS=323km/h IAS P47's advance ratio=126/(4*22.5)=1.4 fw190's advance ratio=126/(3*22.5)=1.86 2)B point=180m/s TAS=648km/h TAS=462km/h IAS P47's advance ratio=2.0 fw190's advance ratio=2.66 3)C point=216m/s TAS=777km/h TAS=555km/h IAS=345m.p.h. IAS P47's advance ratio=2.4 fw190's advance ratio=3.2 dive.JPG B piont--->When both p47 and fw190 dive to 20000ft/462km/h IAS=287m.p.h. IAS, p47's efficiency is 70%, almost twice of fw190's 38%! C point---->When dive to 20000ft/555km/h IAS=345 mph IAS, fw190 almost lost its propellerthrust while p47's remaining 55%. So when speed building up @high altitude, the third part of acceleration formular will also be p47's advantage. Thus we could image how "Thunderbolt" really is! P47's exhaust turbine boost leads to the lost of exhaust boost for propeller, but that can't help fw190 much. Finally, we can completely understand why Republic's engineers want the biggest propeller as possible. Last edited by BlackBerry; 05-13-2012 at 03:38 AM. |
#5
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interesting. I'm suggesting that at point A with a canister of mw50 on board that the 190 guy trade high rpms and prop efficiency while TAS is low, for thrust 'instantaneously' (limited by rate of change of the blade angle) by over-riding auto prop pitch (slower response). The prop would not be spinning at 1350 rpm. It has a load on now, so is spinning at say the lower end of the power curve for the bmw engine, guesstimate, 1050 rpm. Point C for 190 is irrelevant because dive speed limitations are upon him. The race is for point B. How long does it take for p47 turbo to spool up??? How long does it take to get power from mw50???
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#6
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1) German tried MW50 on BMW801 but finally gave up. It's said that MW50 is harmful to BMW801's piston. 1945 version Dora's Jumo213A(liquid cooled) was equipped with MW50. However, 20000ft(6000m) is probably above 190's FTH, so there is little benifit from WEP. At "A" point, if fw190 uses 1050rpm propeller, tip rotating speed is 165m/s, TAS is 126m/s, Mach number=207/310=0.67. Quite below 0.9mach. But I'd to say the propeller's has a certain optimised rpm, if you use full 100% throttle while reducing propeller's rpm incorrectly, you will lose efficiency. Your propeller probably couldn't absorb engine's output. 2) C point is above fw190's max allowable diving limit? 3)I don't know how long does it take for p47 turbo to spool up. I guess it's several seconds? 4)Last but not least, Do you have the information of Dora's 41276.16 V propeller? The size of it, the reduction ratio etc. As we all known before 4.11m, Dora flys so fast. Last edited by BlackBerry; 05-13-2012 at 08:28 AM. |
#7
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#8
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I know you are trying to get best propeller efficiency by adjusting rpm manually, thinking that fw190 is quite an automatic plane but the pilot is oblidged to be so busy....
I'll carefully calculate Fw190 A8's prop. efficiency. Quote:
Prop diameter: 11.98feet=3.33 metre Prop rpm: 2700*0.54=1458rpm =24.2 rps(100% pitch) Notice that "B" point is just Fw190A8 max. level speed @19500 ft, that is 648km/h=180m/s advance ratio=180/(3.33*24.2)=2.23 P47's advance ratio=2.0 So fw190's ratio is NOT so bad as 2.66, just 2.23. My 3-meter vs 4-meter comparation is just a demonstration of how important the diameter of prop. is. ![]() You can see Fw190A8 gets its max. level by using 2700rpm-engine, this is the best rpm for A8, if you fly A8 at "B" point, don't decrease rpm because this will increase your advance ratio, which leads to the moving to rightside on the curve. ![]() At "B" point, A8's tip speed=(180^2+253^2)^0.5=310m/s. Mach number is 310/316=0.981 Mach, almost 1 Mach. That means @19500ft, fw190A8 have to make it's propeller's tip speed just equal to 1 Mach, this is the best result, if you decrease rpm, you lose efficiency because "advance ratio" will be greater. Actually, fw190A8's prop. working piont is "D" with efficiency 0f 60%+, less than P47's 70%, if P47 using 16:9 reduction, thundebolt's working point is "E", 75% efficiency. dive.JPG I am not saying that manual operating rpm is useless, it may help you a bit, but not much. P47's efficiency advantage may or may NOT overcome its huge weight at high speed, but at least P47 could shrink the third part of the formular which is propitious to fw190. Even fw190 could maintain 100% efficiency all along diving, the importance of 3rd part of firmualar will also be less and less. Don't forget another foumular: output(HP)=speed(m/s)*thrust(KN) When you double your speed, the 3rd part of formular will become 50% (and even smaller due to efficiency lose) important as before, the 2nd part will become 400% important as before. When P47 building up speed quickly, fw190A is doomed to be outdived. Last edited by BlackBerry; 05-13-2012 at 11:25 AM. |
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