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#1
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La5 0,025 Why don't you just work backwards and calculate how much different planes should be for separation after dive to meet your expectations. BTW how big the difference should be in your opinion after 2000m vertical dive? Quote:
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Happens online all the time. Quote:
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#2
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It has been known for years that the game accelleration rates are not that accurate. I think the documents from which the games rates are taken are from shallow test dives (as mentioned) so cannot really be extrapolated to 90 degree dives.
In this situation, there probably should be large initial differences due to weight, power and friction, as this was guaranteed escape tactic for the FW, P47 and others, against the lighter aircraft. Maybe TD can tweak the FM's in this area.
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#3
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#4
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The final test would be P47-vs-something else.
We all know that the p47 'dropped like a brick'... if this doesn't happen in comparison to other a/c... we quiet simply have a FM problem .. period! This is a valid, if not 'niche' point brought up by mayshine.. whether anybody likes it or not, is irrelevant. and.. Yes Yes.. we've done the aeronautics and formulae ad-nauseum
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Last edited by K_Freddie; 05-03-2012 at 11:02 PM. |
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#5
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It is time to rethink FM policy...
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#6
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#7
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Actually, it's not "we all know", but "some think". I know that it dropped faster than a brick, and it does in game. A brick neither produces the thrust a P-47 produces, nor is it anywhere near as aerodynamic. However, this applies to about all WW2 fighter aircraft.
Anyway, you are more than welcome to do the research, dig up a few tests and take it from there. |
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#8
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And P-47 falls like the brick in comparison with most other aircrafts. Quote:
FM data you posted for several planes looks like 4.11 data. And JtD is wrong in what exactly? AFAIK F=mg, g is a constant and is the same for every object in game.
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#9
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Take the force triangle for a dive. A component of weight contributes to thrust based on the angle of dive. The difference between the force on the axis of motion in the dive and the force on the axis of motion for level flight is your initial excess force that will move the aircraft to its new equilibrium point velocity. The derivative between that and equilibrium is your average excess force along that vector.... Then apply the same formula... Force = Mass x Acceleration Rearrange it to solve for Acceleration: The acceleration of gravity is considered constant but acceleration is not constant. Acceleration = Force/Mass You then have the aircrafts acceleration rate to the equilibrium point. Now I am not a computer programmer but I am sure there is a way to look at the code to see if it following those principles. Last edited by Crumpp; 05-07-2012 at 03:13 PM. Reason: Removed note on assumption original posters point on dive acceleration is valid, I understand it is not. |
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#10
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But it does. The original poster asked in the topics title why there are no dive acceleration differences. There aren't because gravity is the same for all planes. As soon as you consider anything else, the dive accelerations are different. Had he asked why all the dive accelerations are different, the question would have required a much more complex answer.
The answer was specifically given to the question asked. Last edited by JtD; 05-07-2012 at 06:16 PM. |
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