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IL-2 Sturmovik: Cliffs of Dover Latest instalment in the acclaimed IL-2 Sturmovik series from award-winning developer Maddox Games. |
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#1
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Please show the math that it isn't possible.
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#2
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Go play pool, just replace the white ball with a tiny marble and see what happens. No need for an equation.
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#3
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But if I throw 1000's of marbles at very velocities and are high exsplosive it's different
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#4
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Damn good spot you found here.
![]() ![]() But I have to say, your bait is getting old.
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#5
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The math would not be all that bad, assuming certain simplifications. However it's quite unnecessary. Consider that a P-51 weighs about 9000 pounds. Now I have found that locomotives vary hugely in mass, but let's assume a 50 (imperial) ton locomotive, which is on the low end. That's 100 000 pounds.
The forces subjected on the locomotive cannot be more than the forces of recoil subjected on the aircraft. In fact since a great deal of energy will be expended by the bullets in puncturing the metal of the locomotive, it will in fact be much less, but the force of recoil is an extreme upper limit. If the energy in the bullets was sufficient to throw a train--weighing over 10 times as much as the aircraft--off its tracks then the aircraft would come to a dead stall after only a very short burst. Myths about the A-10 included, this is patently ridiculous. Oh and of course this is just the locomotive itself, it becomes even more absurd if you consider the mass of the train cars. Last edited by Space Communist; 10-25-2011 at 05:56 PM. |
#6
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Yes, but the plane has momentum flying forward which adds a lot to energy in the bullets. Come to think of it, most accounts I have read or seen on TV were pilots flying the P-47. Now if a massive Jug is in a transonic dive firing 1000's of .50 bullets from its 8 guns, that is a real wall of lead traveling at insane speeds. Now these pilots, who were there and saw with their own eyes say they knocked trains off the tracks I will believe them over some random guy on the web.
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#7
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Everyone should note (and Cheesehawk has wisely pointed out) that this is the speed of the bullet as it leaves the barrel, which is something like Mach 3.5 at sea level. The bullet will decelerate rapidly during the time it takes to leave the barrel and strike the target.
Last edited by CaptainDoggles; 10-26-2011 at 01:46 AM. |
#8
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Try some research outside of google and wikipedia for a start |
#9
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Sorta sounds like the same responses you got on the Ubi forums back in April , doesn't it?
![]() http://forums.ubi.com/eve/forums/a/t...819#1501019819 |
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