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| FM/DM threads Everything about FM/DM in CoD |
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#1
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Many early MkV had MkI wings (and fuselages
)Neg G is not near zero G. From the excellent source posted by IvanK (AAAH if all the doc posted on internet had the same trusty quality) , we can see that 0.2G was the design limit. Neg G IMOHO would hve needed a MAJOR redesign of both the carburetor and the fuel supply line. The pumps are far from delivering a sufficient pressure differential). This would be interesting to investigate (both on historic doc and on Warbirds flying nowadays - ie are the Spitfire flying today fitted with US-made pumps ?) |
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#2
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I'm not sure of what was fitted to the aeroplane in the video but what I immediately noticed is that on an inverted flypast the engine spluttered, but not terribly, and maintained power. In game, even with minor moments of low/negative G the prop will grind to halt. So the question is really - what is fitted to this aeroplane?
I also notice the how easy it is to drive the Spit on the ground, never had that in game from any aeroplane. At Duxford the P51's waltz about at taxi but in 1946 they were far harder to move. |
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#3
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Float type carburetor's are not capable of inverted flight as fitted to the Merlin. Quote:
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#4
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The relative wind will drive the propeller and it will continue to spin. A CSP will act as huge airbrake immediately slowing the airplane down at a rapid pace until there is not enough wind to drive the propeller. A fixed pitch propeller will slow the plane down at a much slower pace. |
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#5
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Something not completely related, but interesting non the less. This is a quote from sir Stanley Hooker, no doubt someone from here will be along to say he's wrong, and doesn't know what he's talking about, but hey
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#6
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I think that in many of the maneuvers the throttle would have been cut back to reduce prop torque and aid control.
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#7
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Yes. We shld not forget here that float carb was the norm at the time and pilots were used to fly that way.
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#8
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In the isentropic case, (T2/T1) = (P2/P1)^((gamma-1)/gamma) Isentropic Supercharger work = W*Cp*(T2-T1) Actual Supercharger work = (Isentropic work)/(Isentropic Efficiency) Reducing the temperature upstream of the supercharger therefore reduces the supercharger work at fixed supercharger efficiency, and therefore increases the overall efficiency of the machine. Furthermore, because the supercharger temperature ratio is > 1, it follows that the the temperature reduction in the induction manifold will be correspondingly greater than that due to the evaporation of the fuel alone (though in this case the 25 K figure was measured in the induction manifold, the point is that you wouldn't actually get a 25 K temperature drop from direct fuel injection at TDC). |
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#9
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Well... they call it cold air intake with most of them being not so cold
![]() It works also with a turbocharger Last edited by TomcatViP; 10-12-2011 at 03:15 PM. |
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#10
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Quote:
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