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  #11  
Old 06-06-2012, 01:31 PM
BlackBerry BlackBerry is offline
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Quote:
Originally Posted by Crumpp View Post
You have their power output as the same. They are not the same.

The P47 achieves a Vmax of 339mph on 2300shp and the FW-190A8 achieves 359mph on 1980 shp.
when level flys at Vmax, fw190a8 in equilirium, zero acceleratiom, all forces are balanced.

t=P*r/V=1980*735*0.8/161=7231N

m*g* sin(0)+t=d*Vmax^2

d=t/Vmax^2=7231/161^2=0.2790

when dive in 45 degree, let the new equilirium speed as V:

new engine thrust should be 7231*(161/V)

m*g* sin(45)+t=d*V^2

3500*9.8*0.707+7231*(161/V)=0.2790*V^2

thus

v^3-86918V-4172728=0

Finally, we get V=316.4m/s=1139km/h.


P47D

339mph=151.6m/s

when level flys at Vmax, P47D in equilirium, zero acceleratiom, all forces are balanced.

t=P*r/V=2300*735*0.8/151.6=8921N

m*g* sin(0)+t=d*Vmax^2

d=t/Vmax^2=8921/151.6^2=0.3882>0.2816

Obviuosly ,P47d has more air drag coefficenct due to bigger wing area.


when dive in 45 degree, let the new equilirium speed as V:

new engine thrust should be 8921*(151.6/V)

m*g* sin(45)+t=d*V^2

6000*9.8*0.707+8921*(151.6/V)=0.3882*V^2

v^3-107089V-3483833=0

Finally, we get V=342.4m/s=1232.6km/h>1139km/h.

Last edited by BlackBerry; 06-06-2012 at 02:47 PM.
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