I know you are trying to get best propeller efficiency by adjusting rpm manually, thinking that fw190 is quite an automatic plane but the pilot is oblidged to be so busy....
I'll carefully calculate Fw190 A8's prop. efficiency.
Quote:
BMW-801D 2700rpm VDM 3m diametre has a 0.54 prop reduction gearing. Fw190A8 :VDM 9-12176A, 10 ft, 11 ¾ in. diameter 390 lbs
FockeWulf190 BMW 801D radial VDM prop mechanism was built into the nose case of the engine itself, along with 1.72 to 1 cooling fan drive, 0.54 prop reduction gearing, magneto, oil pump, and front camshaft drive.
http://www.enginehistory.org/Convent...20Electric.pdf
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Prop diameter: 11.98feet=3.33 metre
Prop rpm: 2700*0.54=1458rpm =24.2 rps(100% pitch)
Notice that "B" point is just Fw190A8 max. level speed @19500 ft, that is 648km/h=180m/s
advance ratio=180/(3.33*24.2)=2.23
P47's advance ratio=2.0
So fw190's ratio is NOT so bad as 2.66, just 2.23.
My 3-meter vs 4-meter comparation is just a demonstration of how important the diameter of prop. is.
You can see Fw190A8 gets its max. level by using 2700rpm-engine, this is the best rpm for A8, if you fly A8 at "B" point, don't decrease rpm because this will increase your advance ratio, which leads to the moving to rightside on the curve.
At "B" point, A8's tip speed=(180^2+253^2)^0.5=310m/s.
Mach number is 310/316=0.981 Mach, almost 1 Mach.
That means @19500ft, fw190A8 have to make it's propeller's tip speed just equal to 1 Mach, this is the best result, if you decrease rpm, you lose efficiency because "advance ratio" will be greater.
Actually, fw190A8's prop. working piont is "D" with efficiency 0f 60%+, less than P47's 70%, if P47 using 16:9 reduction, thundebolt's working point is "E", 75% efficiency.
dive.JPG
I am not saying that manual operating rpm is useless, it may help you a bit, but not much.
P47's efficiency advantage may or may NOT overcome its huge weight at high speed, but at least P47 could shrink the third part of the formular which is propitious to fw190. Even fw190 could maintain 100% efficiency all along diving, the importance of 3rd part of firmualar will also be less and less. Don't forget another foumular:
output(HP)=speed(m/s)*thrust(KN)
When you double your speed, the 3rd part of formular will become 50% (and even smaller due to efficiency lose) important as before, the 2nd part will become 400% important as before.
When P47 building up speed quickly, fw190A is doomed to be outdived.