[Mustang]

I hope that someone can understand this

And the reason For the FW 190 D9 has tank ( 39 minutes for water/methanol)


http://horsepowercalculators.net/tun...er-performance

Why is this important for cooling ?
"
The first-order phase transitions are those that involve a latent heat . During such a transition, a system either absorbs or releases a fixed (and typically large) amount of energy. During this process, the temperature of the system will stay constant as heat is added.” … read more

Which means that the water or methanol will try to keep the air / fuel mixture at a fixed temperature of 65*C for the methanol phase change, and 100*C for the water phase change, for a long time (until the entire fuel has changed state) while absorbing a very large amount of heat energy out of the compressed air.

Since the air entering into the water/methanol spray’s path (especially with a lack of an intercooler) can be as high as 100*C above ambient (so with an ambient temperature of about 40*C for under hood temps we’re talking about an air inlet temperature of around 140*C in the intake piping).

Once this 140*C air meets the water & methanol mixture both the water and methanol will attempt to bring down the air / fuel mixture down to 100*C (the boiling point of water) and if all the water has vaporized into steam, then further down to 65*C the boiling point of methanol. If both operations are successful then the final temperature of our mixture is 65*C or 25*C above ambient which is great for any intercooler, and even more impressive for a higher octane non-intercooled system like ours relying on water methanol injection.

Now there are two possible applications for water / methanol injection:

1- The typical added cooling application:

a. In this setup, the water / methanol mix is usually mixed in a 50/50 mix of water and methanol.

b. The jetting is usually about 10-15% the total fuel flow of the system:

For example a 300hp four cylinder car needs four 450cc/min fuel injectors to produce that power figure. Our total fuel flow at peak power is 450cc/min 4 = 1800cc/min or 1.8 liters per minute of fuel.

1 gallon is four liters and 1 hour is sixty minutes so our total fuel consumption is equivalent to 27 gallons per hour of fuel (if you were able to stay at peak hp and rpm for a whole hour).

The reason we’re doing this math is that water / methanol jets are rated in gallons per hour.

So 10 to 15% of 27 gallons per hour = 2.7 to 4.05 GPH injection nozzle.

Now remember that 50% of our mixture is methanol, which is a high octane gasoline. So when injection 15% water methanol mixture with 50% of that being methanol, then our final air fuel ration will be richer by 7% or about 1 AFR point. This means that to reach optimum power again and our optimum air fuel ration we need to either increase boost pressure or retune our car to optimize it for the added high octane fuel.

2- Using methanol as a fuel

In light of what we just mentioned about methanol being a fuel, you could possibly use water /methanol injection as a supplementary stand alone high octane fuel system. The trick here is to keep in mind that the amount of water you spray in the system must be controlled to prevent the engine from hydro lock.

So in using water / methanol as a supplemental fuel as well as a cooling agent, limit the water content to 5 to 7% of your fuel injector flow, and compensate for your added fuel demands with methanol.