[raaaid]

haha i got a zero out of ten in my last physics exam but i bet noone can solve this problem, make it a column of water so density is one:


a special pitot tube with both ends parallel to the flow of wind but oposite sense is in an ideal fluid at an speed of 1 m/s

what will be the height of the mercury(water)?

d*g*z+v*v*d+p=k

edit:

imagining a normal pitot tube in a fluid at 1 m/s answer would be:

1000*10*x+1000+1=1000*10*0+0+1
10000x+1001=1
10000x=1000
x=1/10
0.1m height of column of water