I did made some calculation, and I use Zechnophobe formulas to determine the damage dealt when accounting Attk and Def stats.
http://forum.1cpublishing.eu/showthr...t=10991&page=2
Using this formula the Fairies are delaing more Damage and receiving less (much less without the Double Attack)
Thus we have:
round 1 LF moves, H hit for 1129 killing 141
total health and number of troops: LF 10295 (1287) H 7260 (66)
round 2 LF hit for 1287 killing 11, H step away and hit for 940,5 killing 117
total health and numbers of troop: LF 9355 (1170) H 5973 (55)
round 3 LF hit for 1170 killing 10 H step away and hit for 769,5 killing 96
total health and numbers of troop LF 8585,4 (1074) H 4803 (45)
round 4 LF hit for 1074 killing 9 H step away and hit for 615,6 killing 76
total health and numbers of troop LF 7969,8 (998 ) H 3729 (36)
The Hunter casualties makes them unable to get rid of Fairies fast enough and they keep hitting them, next round they wipe another 9 hunters making it 27.
It appears that the main issue here is how do we calculate damage dealt. Like I said I use the formula posted by Zechnophoe which:
For the fairies, the damages dealt are:
[100/(100+((10/3)*(DIFFERENCE_F)))] * Damage
where Difference_F is the difference between the Hunter Defence and the Fairy attack --> 15
that means the Fairies are doing only 66,6% of their normal damage. Since they are doing 1,5 mean damage, the total damage dealt is equal to the number of fairies units left in the stack
For the hunter the damages dealt are:
[(DIFFERENCE_H * (10/3))/100] * Damage + Damage
where DIFFERENCE_F is the difference between attack of the Hunter and defence of the Fairy --> 24
That means the hunter are doing 80% more damages.
Maybe this formula is wrong. Cause your numbers means they are doing 300%. But Zechnophobe said that
"Both of these calculations max out at 60 difference. At 60 greater attack you will do 300% of base damage (three times normal damage) and at 60 greater defense you will take 33% of normal damage (67% less than normal)."