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#21
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check out the wki article
http://en.wikipedia.org/wiki/Minto_wheel only reference in 100 years is mother erath magazine
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL |
#22
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I see. It has a wiki article but no one knows about it. You'll be a billionaire soon, trust me. |
#23
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The reason no one knows about it is because it is useless in the real world. There are hundreds of better ways to produce power right now. --Outlaw. |
#24
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well outlaw so you belive i did study thermo, check this out:
http://energy.sdsu.edu/testhome/Test...C/TSatR12.html the vapur pressure differnce bewteen top and bottom with a gradient of five degrees its 100 kpa this means the wheel can work with 10 m diametrum on a 5 º gradient how much work is that for kg of r12? 1*10*10=100 J whats the internal energy difference for 5 º around 5 J/kg U variation=Q-W 5=Q-100 Q=105 eficiency=w/q=100/105=95% eficiency negelcting a ten percent of mechanical lost it gives the 85% figure matching the claimed author eficiency if it filtered to the wiki is cause things are changing due to the 2012 effect of next leap of evolution
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL |
#25
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#26
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so whats wrong?
well i saw it: whats the internal energy difference for 5 º around 2000 J/kg U variation=Q-W 2000=Q-100 Q=2100 eficiency=w/q=100/2100=4.7% eficiency eficiency for carnot? 1-cold focus/hot focus=1.3%
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL Last edited by raaaid; 03-05-2012 at 01:18 PM. |
#27
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I have studied thermofluids albeit very briefly but I can tell that your figures just come our of thin air.
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#28
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If you were to work it out you would require a hell of a lot more equations and all the assumptions you made...
It should look more like this http://www.borderschess.org/MintoWhe...tionUpdate.pdf
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#29
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whats the internal energy difference for 5 º
around 2000 J/kg in the best case around 5000 j/kg in the worst case U variation=Q-W 2000=Q-100 Q=2100 eficiency=w/q=100/2100=4.7% eficiency in the worst case: 100/5100=2% maximum eficiency for carnot? 1-cold focus/hot focus=1.3%
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#30
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It's just not that simple you can't just take random figures out of nowhere and except ppl to believe them, if you really did study thermodynamics then get your notes out and work the efficiency out correctly.
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