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Crossworlds Campaigns Questions, strategies, hints and other info about campaigns in KB: Crossworlds.

 
 
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Old 10-19-2010, 01:14 AM
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Zechnophobe Zechnophobe is offline
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So, you questioned my math, for that I must defend my honour!

Odds of you NOT getting a rune, assuming two separate rolls for each:

Per battle = 23/25 * 23/25 = .8464 (84.6%)
For 12 battles = .8464^12 = .1351.. (13.5%)
Odds of getting at least one rune = 1-.1351 = 86.4%

You take the inverse, since the odds of something happening + the odds of it NOT happening = 1.


Quote:
Originally Posted by ckdamascus View Post
[edit]
Ah, been a while since I did probability.

Your odds of getting at least one rune should be even higher, at 87.6% (unless the calculator i'm using is incorrect).

That is assuming that the game intelligently rolls for both belts (would be pretty messed up if it didn't).
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