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#1
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all right basically you see a wall where the wall is cause light rebounds on the wall and your eye caughts that rebounded light
from every point of the wall light will come like this V the big question why when im far from the wall i dont see less light from the wall for im of the top of the V and when im close i recieve more light from being on the apex of the V of rebounded light of the wall or put it other way what would you rather a sky fully covered by suns or a sky fully covered by stars?
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL Last edited by raaaid; 01-14-2013 at 02:53 PM. |
#2
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Why wouldn't you see the same amount of light? Actually, you would recieve slightly less direct light off the wall, as you put it, but at the same time you would be receiving more ambient or environmental light due to the increased 'scope' of what you are seeing further away.
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#3
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thats true if you consider light REFLECTED LIKE IN A MIRROR
but actually its not reflected but once it hits the object light expands like this V i try to use basic logic an object i see it cause emits light, light opens like this V, therefore halving distance to an object should appear 4 times brighter besides 4 times bigger(twice bigger in lenght 4 times in surface) maybe actually colour light is different than sun light?
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#4
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The light you see, (the brightness) is based on how much light is reflected back into your eye - the same way a magnifying glass works - from dim focus, to intense focus which you would burn something with. There is ALWAYS the same packet of light being reflected. Imagine the Sun, and a mirror. You face forwards but the mirror is angled away - therefore you are not in the direct path of the mirror and cannot see it. - (In a perfect world of course)
Light isn't reflected in a V, you have confused yourself. It doesn't come back in both directions. It enters on the left of the V and leaves on the right or vv. ![]() |
#5
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Well he is kinda right about having the distance and that causing light to appear 4 times brighter. Inverse square law and all.
Then again I'm replying to a raaaid thread, so what do I know.
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#6
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I wonder if he is also getting confused about what 'diffusion' is. He thinks a photon of light hits the wall and then gets 'spread' when it bounces off but that single photon still bounces off in one direction and stays the same brightness (ignoring particles in the air etc), just that as the wall is not a perfect mirror it does not bounce off at the same angle as it hit. However other photons that hit the wall at an angle that would not bounce towards his eye in a mirror, will bounce towards his eye because the wall is uneven so the wall looks uniformly lit rather than just showing a reflection of the light source in one place (assuming we are not using very shiny paint)
Inverse square law does not apply to photons; otherwise a candle would be invisible if you were more than a few feet away, hell everything would be invisible! ![]() |
#7
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#8
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Considering that light is a frequency and travels as a wave, it is not as a V that light is reflected off any given object... how would think glare comes about?
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#9
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http://hyperphysics.phy-astr.gsu.edu...sion/isql.html
i think i know whats going on: just the light that is meant to be seen exists, when you dont look at the moon it doesnt exist like that light that rebounds in an object actually goes like this I not like this V for only the light that enter the eye exists ![]()
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3gb ram ASUS Radeon EAH4650 DI - 1 GB GDDR2 I PREFER TO LOVE WITHOUT BEING LOVED THAT NOT LOVE AT ALL |
#10
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All the light and every object it reflects off exists. Just because you can't see it, doesn't mean it's not there.
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