Quote:
Originally Posted by raaaid
well outlaw so you belive i did study thermo, check this out:
http://energy.sdsu.edu/testhome/Test...C/TSatR12.html
the vapur pressure differnce bewteen top and bottom with a gradient of five degrees its 100 kpa
this means the wheel can work with 10 m diametrum on a 5 º gradient
how much work is that for kg of r12?
1*10*10=100 J
whats the internal energy difference for 5 º
around 5 J/kg
U variation=Q-W
5=Q-100
Q=105
eficiency=w/q=100/105=95% eficiency
negelcting a ten percent of mechanical lost it gives the 85% figure matching the claimed author eficiency
if it filtered to the wiki is cause things are changing due to the 2012 effect of next leap of evolution |
Lmao where did you study thermodynamics? Chumpsville by any chance lol