so if a bomber takes 2 gunsights at 100m and 1 at 100 m then how many at 150 m?
 

so if a bomber takes 2 gunsights at 100m and 1 at 200 m then how many at 150 m?



just imagine you have set convergence at 150 m it would be crucial to know

my asumption:

double distance half amount of gunsights so

distance-gunsights:


25-8
50-4
100-2

150-1.5

200-1
400-0.5
800-0.25

is my reasoning correct because if it is theres a glitch in the matrix i think

compare it with a fighter:

distance-gunsights:

25-4
50-2
100-1
150-not 0.75 closer to 1 than to 0.5
200-0.5
400-0.25
800-0.125

No no no no!

Eye, recticle, object! There are three parts to this. This is why anything that is in the ring is scaled by 10. So a fighter with a 10 metres wingspan that fits once is 100m. Fits twice is 200m. Fits 1 and a half times is 150m. The value of multiplication is always a 100th of its actual size. (for the 109 Revi)

30m bomber fits once he is 300m, fits twice is 600m. Fits 1.5 times is 150m.


Wing span or length multiplied by number of times in the recticle multiplied by 100 = Distance to the target.

I've no idea about the sight, but just looking at your maths, are you sure it isn't 450m?




.

Yes you are quite right, I was wrong. Also I noticed its not mulitplied by 100 but 10!


30 times 1 times 10 = 300
30 times 2 times 10 = 600
30 times 1.5 times 10 = 450

From "Schiessfibel" by Adolf Galland:

http://i1020.photobucket.com/albums/...ps9a6e70b2.png

check your maths sir:

a plane takes two gunsights at 50 m

one gunsight at 100

0.5 gunsights at 200 m

but

at 150 m will take 3 times less than at 50 m an 1.5 times less than at 100

and efectively 2/3 = 1/1.5 = 1.666...

oh dejavu all over

I did, they were corrected.

I cant follow your reasoning after the word "but". Sorry.

take as basis a fighter at 100 m takes one gunsight

how many does it take at 200 m? 1/2, it will apeear two times samller than at 100 m

so how many at 150 m? 1/1.5=0.666..., it will appear 1.5 times smaller than at 100 m

not .75

now i wonder where did i discuss this before

1 divided by 1.5 is 0.6667 but this proves nothing...

100 divided by 1 = 100
150 divided by 1.5= 100
200 divided by 2 = 100

This is what I ment what I said its a factor of 100. However this is only for a 10m wing span.


A bomber is 30m's on average.

oki doki, but the real question after that is ............

how can you make sure that the onscreen displayed distant aircraft in your CoD gunsight reticle is 100% displayed correctly in the right size on your pc screen, ie be seen on your monitor in 1:1 correct size comparison as you would see it from that fighter aircraft in real life with the naked eye on the real gunsight reticle ?
note: we are presuming the viewers eyes are at the same distance from their pc screen as they would be in the real cockpit from the real gunsight reticle

:)

hint hint, anybody needs a hint ? :)

Errr do you have some kind of magic 3D monitor? Why would it matter how far away you are from a 2D object (the monitor)?

As for your point - why not spill the beans this is a raaaid thread, might as well add more madness.