![]() |
:cool:
Very nice! |
I like the cut of your jib!
Can't wait to see how it turns outs |
Designing a mechanism that'll use the full range of the spring force.
For example, I have a 40N - 100N spring, and I want to use all of that range. So this translates a 45 degree turn or 1 inch of movement on the wheel, into 4 inches of movement on the spring to get the full range of force . So that I have about 4 kilograms (9 pounds) of force required to move the stick at the center, and about 10 kilograms (22 pounds) to move it all the way, increasing linearly. All the moving parts are connected with ball bearings so the movement should be real smooth. Anyone knows what would be real life values for forces on the stick of these medium bombers in level flight? I read somewhere about 109's forces at 400 mph, 6 kilograms or 13 pounds. I just went from there. http://img441.imageshack.us/img441/270/1413241.gif Uploaded with ImageShack.us |
It is a good looking concept. 6 kgs can be a good value for the elevator but I think its too much for the aileron movement. (at cruising speed at least)
As a thumb rule, aircraft designers use the following force pattern: Aileron: 1x N Elevator: 2X N Rudder: 4x N Where x is the current indicated control force What CAD software do you use? |
Quote:
|
All times are GMT. The time now is 07:35 PM. |
Powered by vBulletin® Version 3.8.4
Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
Copyright © 2007 Fulqrum Publishing. All rights reserved.