Now if only the Spitfire had Fowler flaps .....

The problem is that your turn time of 21 s at 20,000ft is physically impossible. No amount of posturing and posting irrelevant book quotes underlined in red will change that fact:

You have claimed R=900 ft turn radius and turn time T=21 s at 20,000 ft:

Since I'm a metrics guy I will convert R to SI units, i.e. 274.3 m

This gives a turn speed of 82.08 m/s (2*pi*R/T)

So from this we calculate the turn acceleration: a=v**2/R=24.56 m/s**2

So load factor is n= sqrt(a**2+g**2)/g=2.696

Let's calculate the Cl this would require:

n*m*g=0.5*ra*v**2*Cl*S

Spitfire data:

W=6000lb=2724 Kg
S=242 sqft=22.36 m**2
ra=0.65 (Approx at 6.1 Km alt)

Solving for Cl:

CL=(2.696*2724*9.81)/(0.5*0.65*82.08**2*22.36)=1.47

Now NACA claims Clmax for the Spitfire at 1.2 which is a bit low but according to RAE it is 1.36 tops. Your claim leads to a Cl of 1.47 which is clearly unrealistic and like you fails the sanity check.

BTW: I found a RAE report, R&M 2349, Notes on the turning performance of the Spitfire as affected by altitude and flaps.

On page 4 there is a figure 4 which gives the following results for the Spitfire at 20,000 ft: R=1045 ft and T=31.5 s

With my C++ simulations I get R=337 m (1106 ft) and T=31.65 s.

You claim 21 s turn time and 900 ft radius of turn. I get 31.65 s and 1106 ft while Morgan & Morris in R&M get 1045 ft and 31.5 s.

So on the one hand we have C++ simulation data and the data from the RAE report R&M 2349 which seems to tally and on the other hand we have your overbearing attitude and simplistic calculations leading to an off the chart Clmax. What could be the right number I wonder , 21 or 31 s?

Finally, I think the only thing we actually agree on is the other parties lack of formal aerodynamic training. We have been down this road before and as I've told you before I have an Mcs in aeronautical engineering from the Royal Institute of Technology in Stockholm from 1986 and more than 10 years in the business working in the defense industry for Ericsson and SAAB on the Viggen and Gripen fighter systems.

Tell me, What aeronautical companies have you worked with and the Msc in aeronautics from Embry-Riddle you claim to have, which year did you graduate and was that before or after your stint in US Special Forces?;)

Math is good. Me likes math.

:grin:

Me too. In fact, my favourite snakes are adders!

133 mph EAS * .869 = 115.6 KTAS

SMOE @ 20000 feet from our Standard Atmospheric Data = 1.3700

Radius = (VKeas * SMOE)^2 / 11.26tan <theta>

Radius = {115.6*1.3700}^2 / 11.26tan <68>

= 899.97 or just 900 feet @ 20,000 feet

Rate = 1091(tan 68 ) / (115.6KEAS*1.3700)

= 17.05 degrees a second

= 360/17.05 = 21 seconds to complete a 360 degree turn at 20,000 feet


http://img717.imageshack.us/img717/2...erformance.jpg

115.6*1.3700 = 158.4 KTAS

Looks like 21s when we ask the US Navy or use any universal turn performance chart!!

Ha ha ha :eek:

:grin:

The output is only as good as the input...

Yes Holtzauge, I am employed full time in aviation as a pilot.

Yes, I retired from the US Army before I went into aviation as a second career.

How about you? You do C+++++ simulations for a living?

;)

:rolleyes:

http://img819.imageshack.us/img819/4...rnwitflap1.jpg

Anyhow, CL, CD or Cwhatever values mean absolutely NOTHING if reference surface (and reference length for couple of forces) is unknown. Anybody with basic notions in aerodynamics should know this. I can announce CL values of 1700 for a brick if I just select a reference surface small enough if I wish to do so and nobody could claim me wrong.

The CL values in this report are only interesting in relative terms with respect to different flap angles.

Another interesting fact about basic aerodynamics. Coefficient of lift is independent of altitude and corresponds to an specific angle of attack.

In otherwords, the angle of attack for best turn performance will be the same no matter what the altitude.

Amazing that some simple calculations reflect that basic fact. OHH the INSANITY OF IT ALL!!!