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Again, NACA Figure24, Both fw190's 3 meter prop. and p47's 4-meter prop @19500ft , 1350rpm for propeller CSP, 1)A point=126m/s TAS=453km/h TAS=323km/h IAS P47's advance ratio=126/(4*22.5)=1.4 fw190's advance ratio=126/(3*22.5)=1.86 2)B point=180m/s TAS=648km/h TAS=462km/h IAS P47's advance ratio=2.0 fw190's advance ratio=2.66 3)C point=216m/s TAS=777km/h TAS=555km/h IAS=345m.p.h. IAS P47's advance ratio=2.4 fw190's advance ratio=3.2 Attachment 9534 B piont--->When both p47 and fw190 dive to 20000ft/462km/h IAS=287m.p.h. IAS, p47's efficiency is 70%, almost twice of fw190's 38%! C point---->When dive to 20000ft/555km/h IAS=345 mph IAS, fw190 almost lost its propellerthrust while p47's remaining 55%. So when speed building up @high altitude, the third part of acceleration formular will also be p47's advantage. Thus we could image how "Thunderbolt" really is! P47's exhaust turbine boost leads to the lost of exhaust boost for propeller, but that can't help fw190 much. Finally, we can completely understand why Republic's engineers want the biggest propeller as possible. |
interesting. I'm suggesting that at point A with a canister of mw50 on board that the 190 guy trade high rpms and prop efficiency while TAS is low, for thrust 'instantaneously' (limited by rate of change of the blade angle) by over-riding auto prop pitch (slower response). The prop would not be spinning at 1350 rpm. It has a load on now, so is spinning at say the lower end of the power curve for the bmw engine, guesstimate, 1050 rpm. Point C for 190 is irrelevant because dive speed limitations are upon him. The race is for point B. How long does it take for p47 turbo to spool up??? How long does it take to get power from mw50???
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1) German tried MW50 on BMW801 but finally gave up. It's said that MW50 is harmful to BMW801's piston. 1945 version Dora's Jumo213A(liquid cooled) was equipped with MW50. However, 20000ft(6000m) is probably above 190's FTH, so there is little benifit from WEP. At "A" point, if fw190 uses 1050rpm propeller, tip rotating speed is 165m/s, TAS is 126m/s, Mach number=207/310=0.67. Quite below 0.9mach. But I'd to say the propeller's has a certain optimised rpm, if you use full 100% throttle while reducing propeller's rpm incorrectly, you will lose efficiency. Your propeller probably couldn't absorb engine's output. 2) C point is above fw190's max allowable diving limit? 3)I don't know how long does it take for p47 turbo to spool up. I guess it's several seconds? 4)Last but not least, Do you have the information of Dora's 41276.16 V propeller? The size of it, the reduction ratio etc. As we all known before 4.11m, Dora flys so fast. |
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I know you are trying to get best propeller efficiency by adjusting rpm manually, thinking that fw190 is quite an automatic plane but the pilot is oblidged to be so busy....
I'll carefully calculate Fw190 A8's prop. efficiency. Quote:
Prop diameter: 11.98feet=3.33 metre Prop rpm: 2700*0.54=1458rpm =24.2 rps(100% pitch) Notice that "B" point is just Fw190A8 max. level speed @19500 ft, that is 648km/h=180m/s advance ratio=180/(3.33*24.2)=2.23 P47's advance ratio=2.0 So fw190's ratio is NOT so bad as 2.66, just 2.23. My 3-meter vs 4-meter comparation is just a demonstration of how important the diameter of prop. is. http://www.wwiiaircraftperformance.o...90a8-level.jpg You can see Fw190A8 gets its max. level by using 2700rpm-engine, this is the best rpm for A8, if you fly A8 at "B" point, don't decrease rpm because this will increase your advance ratio, which leads to the moving to rightside on the curve. http://www.wwiiaircraftperformance.o...ed-13nov43.jpg At "B" point, A8's tip speed=(180^2+253^2)^0.5=310m/s. Mach number is 310/316=0.981 Mach, almost 1 Mach. That means @19500ft, fw190A8 have to make it's propeller's tip speed just equal to 1 Mach, this is the best result, if you decrease rpm, you lose efficiency because "advance ratio" will be greater. Actually, fw190A8's prop. working piont is "D" with efficiency 0f 60%+, less than P47's 70%, if P47 using 16:9 reduction, thundebolt's working point is "E", 75% efficiency. Attachment 9555 I am not saying that manual operating rpm is useless, it may help you a bit, but not much. P47's efficiency advantage may or may NOT overcome its huge weight at high speed, but at least P47 could shrink the third part of the formular which is propitious to fw190. Even fw190 could maintain 100% efficiency all along diving, the importance of 3rd part of firmualar will also be less and less. Don't forget another foumular: output(HP)=speed(m/s)*thrust(KN) When you double your speed, the 3rd part of formular will become 50% (and even smaller due to efficiency lose) important as before, the 2nd part will become 400% important as before. When P47 building up speed quickly, fw190A is doomed to be outdived. |
This thread is about diving acceleration, not level flying.
"B" point is just fw190a8 's max. level ,only 648km/h TAS, while P51B could reach 715km/h (444mph)@20000ft, and 670km/h for P47D. It's very very easy for P51P47 dive to "C" point(777km/h TAS) which is only 100-60km/h higher than there max. level flght. At "C" point fw190a8 prop. efficiency only 36%! The max. permitted dive speed @20000ft for Tempest is 450 mph IAS=1014 km/h TAS, P47P51 are probably the same. Sir, when diving at 850km/h TAS@20000ft, can you imagine how frustrated fw190A8 is? I think I've expressed enough my opinion. Let's read a paragragh from wiki to understand why the author wrote "energy-saving" dive. "energy saving" means P47's opponents bleeding their energy heavily when fighting against P47 at high TAS. I wish Daidalos team could make il2 perfect by giving us REAL thunderbolt , Mustang, and Tempest.:) Quote:
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But to maintain top speed at level flight, agree. don't use manual mode for that. Maybe they called it 'thunderbolt' because of the dive limit? Okay, I'm out. Thanks for the discussion.:cool: |
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It's totally useless for having 1 Mach dive limit when your enemy could outdive you with better acceleration within 0.7 Mach and pull to level run away. Even if you fly the same a/c 500m behind your wingman, you couldn't catch up him when following his dive, could you? Quote:
Although SpitfireIX/XIV has the same dive limit(if not better than) as fw190A/bf109G, he couldn't over take Germans in a dive. Quote:
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mach 1, sound barrier and 'loud noise'. what is 'thunder'??? get it now??? What other WW2 prop planes had mach 1 dive limit??? I can't recall any other that did. Even the great Ta 152 falls short. So, if Republic makes the only plane that can get to sound barrier with out breaking up, calling it 'thunderbolt', seems a good fit to me. So, I simply was speculating on the origination of name. :rolleyes:
"it's totally useless for having 1 Mach dive limit when your enemy could outdive you with better acceleration within 0.7 Mach and pull to level run away. Even if you fly the same a/c 500m behind your wingman, you couldn't catch up him when following his dive, could you?" Huh? We already know that the fw190a-4 was quicker off the line in the dive! Go back and read your own posts and theory as to why. I already stated your conclusion seemed reasonable. I don't know why you seem to be contradicting your own conclusion now? Most of the other prop planes couldn't touch that dive limit, so p47 acceleration is moot beyond their dive limits. But it did not have the best acceleration in the dive as per the test record. Also, even if fw 190 does get some lucky shots off in the first part of the dive, p47 is built like a tank. Good chance it gets home.;) |
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It's totally useless for having 0.85 Mach dive limit when your enemy could outdive you with better acceleration within 0.7 Mach and pull to level run away. It's totally useless for having 0.75 Mach dive limit when your enemy could outdive you with better acceleration within 0.65 Mach and pull to level run away. It's totally useless for having 0.65 Mach dive limit when your enemy could outdive you with better acceleration within 0.55 Mach and pull to level run away. Now, do you understand me? Quote:
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No, no, no. When hit ground, the speed of fw190 is BELOW its diving limit. But fw190 was outdived by P47, wasn't it? I'll use estimated numbers to show you, if you don't aunderstand, I 'll give up. acceleration=g*cos(65)-dragcoefficent*(TAS)^2/weight+Propellerthrust/weight 1)from 400km/h to 570km/h,Fw190G outdives P47D acceleration=g*cos(65)-dragcoefficent*(TAS)^2/weight+Propellerthrust/weight For fw190G:acceleration=4.1-1.5+3.5=6.1 m/s^2 For P47D:acceleration=4.1-1+2=5.1 m/s^2 6.1>5.1, So fw190G outdives P47D. 2)from 570km/h to 750km/h, P47D doutdives fw190G For fw190G:acceleration==4.1-5+1=0.1m/s^2 For P47D:acceleration=4.1-3.3+1=1.8 m/s^2 1.8>0.1,So P47D outdives fw190G. |
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